A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30N is applied in the direction parallel to surface of the table, the block slides through a distance of 50 m in an interval of time 10s. Coefficient of kinetic friction is (given, g = 10 ms -2 ):
Text Solution
Verified by ExpertsThe correct answer is:
C
a = l m/s 2
= ma
30 - 
x 50 = 5 x 1
50 
= 25
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